Geodesic curvature

In Riemannian geometry, the geodesic curvature $k_{g}$ of a curve $\gamma$ measures how far the curve is from being a geodesic. For example, for 1D curves on a 2D surface embedded in 3D space, it is the curvature of the curve projected onto the surface's tangent plane. More generally, in a given manifold ${\bar {M}}$ , the geodesic curvature is just the usual curvature of $\gamma$ (see below). However, when the curve $\gamma$ is restricted to lie on a submanifold M {\displaystyle M} M of M ¯ {\displaystyle {\bar {M}}} {\bar {M}} (e.g. for curves on surfaces), geodesic curvature refers to the curvature of $\gamma$ in M and it is different in general from the curvature of $\gamma$ in the ambient manifold ${\bar {M}}$ . The (ambient) curvature k of $\gamma \( depends on two factors: the curvature of the submanifold M in the direction of\( \gamma$ (the normal curvature $k_{n})$ , which depends only on the direction of the curve, and the curvature of γ {\displaystyle \gamma } \gamma seen in M (the geodesic curvature $k_{g})$ , which is a second order quantity. The relation between these is $k={\sqrt {k_{g}^{2}+k_{n}^{2}}}$ . In particular geodesics on M have zero geodesic curvature (they are "straight"), so that $k=k_{n}$ , which explains why they appear to be curved in ambient space whenever the submanifold is.

Definition

Consider a curve $\gamma$ in a manifold ${\bar {M}}$ , parametrized by arclength, with unit tangent vector $T=d\gamma /ds$ . Its curvature is the norm of the covariant derivative of } T: $k=\|DT/ds\|$ . If $\gamma$ lies on M, the geodesic curvature is the norm of the projection of the covariant derivative $DT/ds$ on the tangent space to the submanifold. Conversely the normal curvature is the norm of the projection of $DT/ds$ on the normal bundle to the submanifold at the point considered.

If the ambient manifold is the euclidean space $\mathbb {R} ^{n}$ , then the covariant derivative $DT/ds$ is just the usual derivative $dT/ds.$

Example

Let M be the unit sphere $S^{2}$ in three-dimensional Euclidean space. The normal curvature of $S^{2}$ is identically 1, independently of the direction considered. Great circles have curvature } k=1, so they have zero geodesic curvature, and are therefore geodesics. Smaller circles of radius r will have curvature 1/r and geodesic curvature $k_{g}={\frac {\sqrt {1-r^{2}}}{r}}$ .

Some results involving geodesic curvature

The geodesic curvature is none other than the usual curvature of the curve when computed intrinsically in the submanifold M . It does not depend on the way the submanifold ${\bar {M}}$ .
Geodesics of M have zero geodesic curvature, which is equivalent to saying that $DT/ds$ is orthogonal to the tangent space to M .
On the other hand the normal curvature depends strongly on how the submanifold lies in the ambient space, but marginally on the curve: $k_{n}$ only depends on the point on the submanifold and the direction T, but not on $DT/ds$ .
In general Riemannian geometry, the derivative is computed using the Levi-Civita connection ${\bar {\nabla }}$ of the ambient manifold: $DT/ds={\bar {\nabla }}_{T}T$ . It splits into a tangent part and a normal part to the submanifold: ${\bar {\nabla }}_{T}T=\nabla _{T}T+({\bar {\nabla }}_{T}T)^{\perp }$ . The tangent part is the usual derivative $\nabla _{T}T$ in M (it is a particular case of Gauss equation in the Gauss-Codazzi equations), while the normal part is $\mathrm {I\!I} (T,T)$ , where $\mathrm {I\!I}$ denotes the second fundamental form.

The Gauss–Bonnet theorem.