ART

3, Prime Number, Deficient Number, Fibonacci Number

\( {\displaystyle 3=1^{3}+1^{3}+1^{3}=4^{3}+4^{3}+(-5)^{3} } \)

3 is the sum of 3 positive cubes in exactly 1 way.

\( {\displaystyle 3=569\ 936\ 821\ 221\ 962\ 380\ 720^{3}+(-569\ 936\ 821\ 113\ 563\ 493\ 509)^{3}+(-472\ 715\ 493\ 453\ 327\ 032)^{3}.} \)

23 - 1 = 7

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