{\displaystyle 1 = (9b^{4})^{3}+(3b-9b^{4})^{3}+(1-9b^{3})^{3} }
1 = (1 - 9t^{3} + 648t^{6} + 3888^t{9})^3 + (- 135t^{4} + 3888t^ {10})^3 +(3t - 81t^{4} - 1296t^{7} - 3888t^{10})^3
1 = .44/.4 4 = 4.4/4.4 = 44!/44!
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